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-0.7x^2+0.4x+2=0
a = -0.7; b = 0.4; c = +2;
Δ = b2-4ac
Δ = 0.42-4·(-0.7)·2
Δ = 5.76
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.4)-\sqrt{5.76}}{2*-0.7}=\frac{-0.4-\sqrt{5.76}}{-1.4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.4)+\sqrt{5.76}}{2*-0.7}=\frac{-0.4+\sqrt{5.76}}{-1.4} $
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